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2 · 5. A rectangular pit 1.4 m long, 90 cm broad and 70 cm deep was dug and 1000 bricks of base 21 cm by 10.5 cm were made from the earth dug out. Find the height of each brick. Solution: Here l = 1.4 m = 140 cm, b = 90 cm and h = 70 cm. Volume of rectangular pit = l × b × h = (140 × 90 × 70) cm 3 = 882000 cm 3. Volume of brick = 21 × 10.5 ×
A road roller is 140 cm long Its diameter is 84 cm Iy takes 1000 complete revolutions once over to level the road find the cost of levelling the road at RS 50 per square m Maths NCERT Solutions Board Paper Solutions
2018-2-26 · A metallic pipe is 0.7 cm thick. Inner radius id 3.5 cm and length is 5 dm. Find its total surface area. A silver paper covers a packet of 10 choclates Coin of radiud 2cm and 7mm thickness. How much paper need to cover 1000
2020-1-30 · Find an answer to your question A road rolled is 140 cm long . its diameter is 84 cm . it takes 1000 complete revolutions once over to level the road. find the kriya8404 kriya8404 30.01.2020 Math Secondary School answered A road rolled is 140 cm long . its diameter is 84 cm . it takes 1000 complete revolutions once over to level the road
The roller is cylindrical in shape and hence it is considered as a right circular cylinder. In one revolution, the area covered will be the curved surface area of the roller. Since it takes 500 complete revolutions to move once over to level a playground, the area of the playground will be equal to 500 times the curved surface area of the roller.
2017-9-26 · Height of road roller = 140 cm. Diameter of road roller = 77cm Radius of road roller = 38.5 cm. Road roller is in the shape of cylinder . Curved surface area of cylinder = Curved surface area of road roller = = Area covered in 1 revolution = 33849.2 sq.cm. Area covered in 300 revolutions = Since a road roller makes 300 revolutions to level a
2013-3-12 · Part of a roller-coaster ride involves coasting down an incline and entering a loop 30.0 m in diameter. For safety considerations, the roller coasters speed at the top of the loop must be such that the force of the seat on a rider . Geometry. A road 1.6 km long rises 400 m. What is the angle of elevation of the road?
2 · In one revolution, the roller will cover an area equal to its lateral surface area. Thus, in 1 revolution, area of the road covered = 2πrh = 2 x `22/7` x 42 cm x 1m = 2 x `22/7` x `42/100` m x 1 m = `264/400 m^2` In 750 revolutions, area of the road covered = `(750 xx 264/100) m^2`
2013-3-10 · A road roller is 140cm long Its diameter is 84cm It takes 1000 complete revolutions once over to level the road Find the cost of levelling the road at Rs 50 per 100 square meter please answer ASAP Maths Mensuration Area Of Road To Be Levelled = CSA Of Roller X Nuer Of Revolutions. CSA Of Roller = 2*22/7*42*140 = 36960 cm 2. Area Of
It is given in the question that the roller is revolved 500 times to level the entire playground. So the total levelled area of the playground will be equal to 500 times the area of the roller. The shape of the roller is a cylinder. So, we have to basically find the curved area of the cylinder which has diameter =84cm and length 120cm.
A cylindrical road roller made of iron is 1 m long Its inner diameter is 54 cm and the thickness of the iron sheet rolled into the road roller is 9cm Find the weight of the roller if 1cm3 of iron weights It is given that the road roller is 1 m long. That implies the height of the cylinder, h=1m=100cm. Inner diameter =54cm, which implies the
In one revolution, the roller will cover an area equal to its lateral surface area. Radius of the road roller r = 84/2 cm = 42 cm. Length of the road roller, h = 1 m = 100 cm. In 1 revolution, area of the road covered = 2πrh = 2 × 22/7 × 42 × 100 = 26400 cm² = 2.64 m². In 750 revolutions area of the road covered = 750 × 2.64 m² = 1980 m²
2016-1-8 · Grid Rollers; The following types of road rollers are generally used. 1. Cylindrical Roller. This is a light roller of iron, concrete or stone; drawn by hand or bullocks. The size varies, but it is generally about 1 metre in dia. and about
2022-4-30 · Length of the roller (h) = 120 cm Diameter of the roller (d) = 84 cm Thus, the radius of the roller (r) = 84/2 = 42 cm Curved surface area of the roller = 2πrh = 2 × (22/7) × 42 × 120 = 44 × 720 = 31680 sq.cm That means, the area covered by the roller in 1 revolution = 31680 sq.cm Now, the area covered by the roller in 500 revolutions
2 · 5. A rectangular pit 1.4 m long, 90 cm broad and 70 cm deep was dug and 1000 bricks of base 21 cm by 10.5 cm were made from the earth dug out. Find the height of each brick. Solution: Here l = 1.4 m = 140 cm, b = 90 cm and h = 70 cm. Volume of rectangular pit = l × b × h = (140 × 90 × 70) cm 3 = 882000 cm 3. Volume of brick = 21 × 10.5 ×
A cylindrical road roller made of iron is 1 m long.Its internal diameter is 54 cm and the thickness of the iron sheet used in making the roller is 9 cm.Find the mass of the roller, if 1 cm 3 of iron has 7.8 gm mass. Internal radius of the cylindrical road roller = 27 cm = r (as we know that the radius is half of the diameter) Given the
The diameter of a road roller 1 m 40 cm long is 80 cm. If it takes 600 revolutions to level a playground, find the cost of levelling this ground at the rate of 1.50 per sq m. < PreviousNext > Answer. soek Length: lm 40cm = 1.400 diomiter = 80cm=0.8m radies 2 0.82 0.4m 2. Distance covered 22 x radiusxlength z 2xx(0.4)×(1.4) 22x22 x 0656 x
2018-5-29 · Ex 13.2, 4 The diameter of a roller is 84 cm and its length is 120 cm. It takes 500 complete revolutions to move once over to level a playground. Find the area of the
2013-3-10 · A road roller is 140cm long Its diameter is 84cm It takes 1000 complete revolutions once over to level the road Find the cost of levelling the road at Rs 50 per 100 square meter please answer ASAP Maths Mensuration Area Of Road To Be Levelled = CSA Of Roller X Nuer Of Revolutions. CSA Of Roller = 2*22/7*42*140 = 36960 cm 2. Area Of
S = 2 π r h. Where r is radius and h is height of cylinder. Complete step-by-step answer: In the given question the diameter of the cylinder is 120 cm. So radius (r) of cylinder is r = 120 c m 2 = 60 c m. Height of the cylinder is 84 cm. Hence curved surface area (S) of cylinder is. ⇒ S = 2 π r h. ⇒ S = 2 × 22 7 × 60 × 84.
2021-10-13 · A road roller is 350 cm long and its diameter is 84 cm. It takes 500 complete revolutions to travel the road. The area covered by it in m² will be: a. 4620. b. 6420. c. 2460. d. 4260 _____ CSA of cylinder = 2πrh. CSA= 2×22/7×84/2×350. CSA= 92400cm². Area of square = CSA× revolution. Area of square = 92400×500. Area of square = 46200000 cm²
2018-12-12 · Transcript. Ex 11.3, 9 A road roller takes 750 complete revolutions to move once over to level a road. Find the area of the road if the diameter of a road roller is 84 cm and length is 1 m. Given, Length of roller = h = 1 m & Diameter of the roller = 84 cm ∴ Radius of the roller = r = 84/2 cm = 42 cm = 42/100 m Given, the roller takes 750
2021-1-17 · Find an answer to your question Road roller 140 cm long and 77 cm in diameter makes 100 revolutions to level a field completely. Find the area in (sq.m) of the OalishaO OalishaO 17.01.2021 Math Primary School answered Road roller 140 cm long and 77 cm in diameter makes 100 revolutions to level a field completely. Find the area in (sq.m) of
2013-3-12 · Part of a roller-coaster ride involves coasting down an incline and entering a loop 30.0 m in diameter. For safety considerations, the roller coasters speed at the top of the loop must be such that the force of the seat on a rider . Geometry. A road 1.6 km long rises 400 m. What is the angle of elevation of the road?
A road roller is cylindrical in shape Its circular-class-10-maths-CBSE. A road roller is cylindrical in shape. Its circular end has a diameter 200 cm and its length is 1.4 m. Find the least nuer of revolutions that the roller must make in order to level a playground of dimensions 125m. ×.